文字列のコピー

明解Ｃ言語入門編 > 11. 文字列とポインタ >

C



#include <stdio.h>

#include <string.h>
char* str_cpy(char* d, const char* s)

{

    char* t = d;
    while (*d++ = *s++)

        ;
    return t;

}
int main(int argc, char* argv[])

{

    int i;

    char* st1 = "12345";

    char* st2 = "ABC";
    printf("st1 = %s\n", st1);

    printf("st2 = %s\n", st2);

    puts("");
    str_cpy(st1, st2);

    printf("st1 = ");

    for (i = 0; i < 5; i++)

        if (st1[i] == '\0')

            putchar(' ');

        else

            putchar(st1[i]);

    putchar('\n');

    printf("st2 = %s\n", st2);

    puts("");
    st1 = "12345";

    strcpy(st1, st2);

    printf("st1 = ");

    for (i = 0; i < 5; i++)

        if (st1[i] == '\0')

            putchar(' ');

        else

            putchar(st1[i]);

    putchar('\n');

    printf("st2 = %s\n", st2);

    puts("");
    return 0;

}

実行結果



T:\>lesson085\project1.exe

st1 = 12345

st2 = ABC
st1 = ABC 5

st2 = ABC
st1 = ABC 5

st2 = ABC