多次元配列の受け渡し

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多次元配列の受け渡し

C


#include <stdio.h>

void mat_add(const int ma[][3], const int mb[][3], int mc[][3])
{
int i, j;
for (i = 0; i < 2; i++)
for (j = 0; j < 3; j++)
mc[i][j] = ma[i][j] + mb[i][j];
}

int main(int argc, char* argv[])
{
int ma[2][3] = {{1, 2, 3}, {4, 5, 6}};
int mb[2][3] = {{6, 3, 4}, {5, 1, 2}};
int mc[2][3] = {0};

mat_add(ma, mb, mc);

int i, j;
for (i = 0; i < 2; i++)
{
for (j = 0; j < 3; j++)
printf("%3d", mc[i][j]);
putchar('\n');
}

return 0;
}

実行結果


R:\>lesson051\project1.exe
7 5 7
9 6 8

Delphi


program Project1;

{$APPTYPE CONSOLE}

uses
SysUtils;

type
TMyArray = array[1..2, 1..3] of Integer;

procedure mat_add(const ma:TMyArray; const mb:TMyArray; var mc:TMyArray);
var
i, j: Integer;
begin
for i := 1 to 2 do
for j := 1 to 3 do
mc[i, j] := ma[i, j] + mb[i, j];
end;

var
ma: TMyArray = ((1, 2, 3), (4, 5, 6));
mb: TMyArray = ((6, 3, 4), (5, 1, 2));
mc: TMyArray;
i, j: Integer;
begin
mat_add(ma, mb, mc);

for i := 1 to 2 do
begin
for j := 1 to 3 do
write(format('%3d', [mc[i, j]]));
writeln('');
end;
end.

実行結果


S:\>lesson051\project1.exe
7 5 7
9 6 8

Perl
sub mat_add
{
    ($ma, $mb, $mc) = @_;
    
    foreach $i(0..1)
    {
        foreach $j(0..2)
        {
            $$mc[$i][$j] = $ma[$i][$j] + $mb[$i][$j];
        }
    }
}

@ma  = ([1, 2, 3], [4, 5, 6]);
@mb  = ([6, 3, 4], [5, 1, 2]);
@mc  = ([], []);

&mat_add(\@ma, \@mb, \@mc);

foreach $i(0..1)
{
    foreach $j(0..2)
    {
        printf("%3d", $mc[$i][$j]);
    }
    print "\n";
}

実行結果

L:\>perl lesson_06_051.pl
7 5 7
9 6 8

Ruby
def mat_add(a, b, c)
    for i in 0..1
        for j in 0..2
            c[i][j] = a[i][j] + b[i][j]
        end
    end
end

ma  = [[1, 2, 3], [4, 5, 6]]
mb  = [[6, 3, 4], [5, 1, 2]]
mc  = [[], []]

mat_add(ma, mb, mc)

for i in 0..1
    for j in 0..2
        printf("%3d", mc[i][j])
    end
    puts ""
end

実行結果

L:\>ruby l:\lesson_06_051.rb
7 5 7
9 6 8